poker hands wikipedia

Is my teacher wrong in this probability problem?

For our probability chapter we have to solve the probabilty of getting each hand in poker. So the first problem is a pair, she helped me and told me it was as follows:
13C1 times 4C2 times 48C3 over 52C5 which turned out to be 1349088 over 2598960 but then I looked to check my answer on the Internet since she sometimes can be wrong. A different way was posted and it came a different way even wikipedia had a different solution. So is my teacher wrong and if so can you explain why because she doesn't take being incorrect lightly? If she is right then can you explain how? Thanks in advance

the correct logic is
[from 13 ranks, choose 1]*
[from 4 of that rank, choose 2]*
[from 12 remaining ranks, choose 3]*
[from 4 of EACH such rank, choose 1] /
[from 52 total, choose any 5]

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= 13C1*4C2*12C3*(4C1)^3 / 52C5
= 1098240/2598960
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what your teacher ha calculated is the probability that there are
AT LEAST 2 cards of the same rank.
by using 48C3, you are allowing ANY 3 cards from 48
whereas they need to be cards of different ranks