Probability And Poker
probability and poker
Probability Question? Involving poker hands?
Need help with this one:
In poker the probability of being dealt a flush, a straight, and a straight flush are .0019654, .0039246, and .0000154, respectively. What is the probability of being dealt a straight or a flush?
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P(A) = .0019654
P(B) = .0039246
P(AnB) = .0000154
P(A or B) = P(A) + P(B) - P(AnB) = .0058746
The intuition behind this is that the probability of A plus the probability of B includes the probability of A AND B twice. So, to undo the double counting, one must subtract the probability of A and B once from the sum.
